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11+10x-x^2=0
We add all the numbers together, and all the variables
-1x^2+10x+11=0
a = -1; b = 10; c = +11;
Δ = b2-4ac
Δ = 102-4·(-1)·11
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-12}{2*-1}=\frac{-22}{-2} =+11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+12}{2*-1}=\frac{2}{-2} =-1 $
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